Question 287637
How can we put this in familiar form?
9 and 4 are perfect squares. These are hints at something.
we know a^2-b^2 = (a+b)(a-b)

we can do this! x^2^2-3^2=(x^2+3)(x^2-3)=0
3^2+3=0, x=Square root of 3i
3^2-3=0, x=Square root of 3

This is not as complicated as it looks, but you must use the common products of Algebra AND be on the look-out for perfect squares either in the exponents or the real numbers themselves.

square root of 3i AND the square root of 3 are the answers.