Question 287067
{{{25x^2 + 40x + 16 = 28}}}
I can see that the left side is
{{{(5x + 4)^2, so
{{{(5x + 4)^2 = 28}}}
Take the square root of both sides
{{{5x + 4 = sqrt(4)*sqrt(7)}}}
{{{5x + 4 = 2*sqrt(7)}}}
{{{5x = 2*sqrt(7) - 4}}}
{{{x= (2*sqrt(7) - 4)/5}}}
and
{{{x = (-2*sqrt(7) - 4)/5}}}