Question 287002
Let x = the First Number, x+1 = the second number

{{{x(x+1) = x + 16}}}
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{{{x^2 + x = x + 16}}} subtract x and -16 from both sides
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{{{x^2 - 16 = 0}}} factor
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{{{(x + 4) (x - 4)}}}
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Answers:  4, -4.