Question 286790
{{{(y^2-9)/(y^2+3y-18)}}} Start with the given expression.



{{{((y+3)(y-3))/(y^2+3y-18)}}} Factor the numerator.



{{{((y+3)(y-3))/((y+6)(y-3))}}} Factor the denominator.



{{{((y+3)*highlight((y-3)))/((y+6)*highlight((y-3)))}}} Highlight the common terms.



{{{((y+3)*cross((y-3)))/((y+6)*cross((y-3)))}}} Cancel out the common terms.



{{{(y+3)/(y+6)}}} Simplify



So {{{(y^2-9)/(y^2+3y-18)=(y+3)/(y+6)}}} where {{{y<>-6}}} or {{{y<>3}}}