Question 34515
{{{ ((x^2-x)/(x^2+3x+2))/((x^2+2x)/(x^2-1)) }}}
Factor all parts of the fractions
{{{ ((x)(x-1)/(x+1)(x+2))/((x)(x+2)/(x+1)(x-1)) }}}
Since this is a Complex fraction .... follow this rule :
{{{ (((A)/(B))/((C)/(D))) = AD/BC }}}
{{{ ((x)(x-1)(x)(x+2))/((x+1)(x-1)(x+1)(x+2)) }}}
Cancel
{{{ ((x)(x))/((x+1)(x+1)) }}}
{{{ x^2 / (x+1)^2 }}}