Question 286786
find the vertex of the parabola F(x)=x^2-16x+63
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Vertex occurs where x = -b/2a = 16/2 = 8
f(8) = 8^2-16*8+63 = -1
Vertex: (8,-1)
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{{{graph(400,300,-10,20,-10,150,x^2-16x+63)}}}
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Cheers,
Stan H.