Question 286770
A stats practitioner wishes to test the following hypothesis 
H0:μ = 600 against 
H1:&#956;<600. 
A sample of 50 observations yielded the statistics: mean = 585 and standard deviation = 45. The test statistic of a test to determine there is enough evidence at the 10% signigicance level to reject the null hypothesis is?
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t(585) = (585-600)/[45/sqrt(50)] = -2.3570
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Cheers,
Stan H.