Question 286710
A department store manager claims that at least 45% of persons who visited this store make a purchase. In a sample of 400 persons who visited the store 150 made a purchase. Test the manager’s claim at the 3% significance level. 
a. State the null and alternate hypothesis.
Ho: p >= 0.45
Ha: p < 0.45
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b. Determine the rejection region for the decision rule.
invNorm(0.97) = -1.8808
Reject region is all z < -1.8808
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c. Which equation listed below would you use?
Equations were not listed.
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d. Using the statistical calculator or manual calculation what is the observed statistic and what is your decision regarding the null hypothesis.
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stat test: z(150/400) = (0.375-0.45)/sqrt[0.45*0.55/400] = -3.0151 
 Provide a one sentence answer.
Since the test stat is in the rejection region, reject Ho.
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Cheers,
Stan H.