Question 286562
triangle CAT has vertices c(4,9) A(8,-9) T(-6,5)
A. find the cordinates of the midpoints of each side of the triangle.
Find the midpoints by getting the average of x and y separately.
for CA: 
x = (4+8)/2 = 6
y = (9-9)/2 = 0
MP at (6,0)
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for AT: MP at (1,-2)
for CT: MP at (-1,7)
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B. Find the length of the median from point C to TA.
distance from C to MP of TA
{{{d = sqrt(diffy^2 + diffx^2)}}}
{{{d = sqrt(3^2 + 11^2)}}}
{{{d = 4sqrt(15)}}}
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C. Find the perimeter of triangle CAT.
P = CA + AT + TC
{{{P = 2sqrt(85) + 14sqrt(2) + 2sqrt(29)}}}
P =~ 49.008
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D. Find the perimeter of the triangle formed in part a above.
= {{{sqrt(29) + sqrt(85) + sqrt(98)}}}
=~ 24.504
E. How do the perimeters in parts c and d compare? 
The smaller is 1/2 the larger.
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