Question 286513
{{{sqrt((3x+7)^2)=3x+7}}} is only true if {{{(3x+7)>=0}}} since {{{sqrt((3x+7)^2)=abs(3x+7)}}} for all values of 'x'. So the answer is 'sometimes true'.


Here are some examples: If x=0, then {{{sqrt((3(0)+7)^2)=3(0)+7}}} ---> {{{sqrt(7^2)=7}}} ----> {{{7=7}}} which is true.


However, If x=-10, then {{{sqrt((3(-10)+7)^2)=3(-10)+7}}} ---> {{{sqrt((-28)^2)=-28}}} ----> {{{28=-28}}} which is false.