Question 286451
If 60% of all woman work outside the home. In a random sample of 20 woman what is the probability that:
Binomial Problem with n = 20 ; p = 0.6
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a. exactly 15 are employed
P(x = 15) = 20C15(0.6)^15*(0.4)^5 = 0.0746...
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b. at least 10 are employed
P(10<= x <=15) = 1 - binomcdf(20,0.6,9) = 0.8725
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c. at most 5 are not employed
P(not employed) = 0.4
P(0<= x <=5) = binomcdf(20,0.4,5) = 0.1256
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Cheers,
Stan H.