<PRE><B>Question 286406</B>
At the beginning of a walk, Roberto and Juanita are 2.2 miles apart. 
If they leave at the same time and walk in the same direction, Roberto overtakes Juanita in 11 hours.
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Juanita distance = &quot;x&quot; miles ; Roberto distance = &quot;x+2.2&quot; miles
Time for both is 11 hrs.
Juanita rate = x/11 mph ; Roberto rate = (x+2.2)/11 mph
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If they walk towards each other, they meet in 1 hour.
Juanita distance = y miles ; Roberto distance = 2.2-y miles
Time for both is 1 hr.
Juanita rate = y mph ; Roberto rate = (2.2-y) mph
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What are their speeds?
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Equations:
Juanita rate: x/11 = y
Roberto rate: (x+2.2)/11 = 2.2-y
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y = x/11
y = 2.2 - [(x+2.2)/11]
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x/1l = 2.2 -[(x+2.2)/11]
x = 24.2 - (x+2.2)
2x = 22
x = 11 miles
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Juanita rate = x/11 = 1 mph
Robert rate = 2.2-1 = 1.2 mph
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Cheers,
Stan H.
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