Question 286251
{{{(x+3)/(3x-1)-(8x^2+8x+3)/(3x^2-7x+2)+(2x+3)/(x-2)}}}
Good job in using parentheses
The key to this expression is noticing that {{{3x^2-7x+2}}} can be factored into the other two denominators {{{(3x-1)}}} and {{{(x-2)}}
so the lcd is {{{(3x-1)*(x-2)}}} so multiply the first fraction by {{{(x-2)/(x-2)}}}
and the third by {{{(3x-1)/(3x-1)}}}