Question 34490
Solve for y:
{{{x = (5)ln(7+3y)}}} First divide both sides by 5.
{{{x/5 = ln(7+3y)}}} Convert to exponential form:
{{{ln(x) = y}}}means{{{e^y = x}}} so for your problem:
{{{ln(7+3y) = x/5}}} means:
{{{e^(x/5) = (7+3y)}}} Subtract 7 from both sides.
{{{e^(x/5)-7 = 3y}}} Finally, divide both sides by 3.
{{{y = (e^(x/5)-7)/3}}} ...and there you have it!