Question 286268
A good way to start is a scatter plot to see how the data points are distributed.
.
{{{drawing(500,500,-10,10,-10,10,
grid(1),
blue(circle(0,2,.15)),
blue(circle(1,0,.15)),
blue(circle(2,0,.15)),
blue(circle(3,2,.15)),
blue(circle(4,6,.15))
)}}}
.
That looks like a parabola, so you're trying to fit a set of points to a quadratic equation.
.
y = x^2
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But we can see the graph needs to be shifted to the right by about 3/2 and it needs to drop by about -1/3.
.
So it looks like:
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y = (x-3/2)^2 - 1/3
.
Graphing we find.
.
{{{drawing(500,500,-10,10,-10,10,
grid(1),
blue(circle(0,2,.15)),
blue(circle(1,0,.15)),
blue(circle(2,0,.15)),
blue(circle(3,2,.15)),
blue(circle(4,6,.15)),
graph(500,500,-10,10,-10,10,(x-3/2)^2 -1/3)
)}}}
.
Looks like a pretty good fit to me...
.
Done.