Question 286293
You are trying to throw a ball over a wire that is 40 ft above the ground.
 The height of the ball is modeled by the equation h=-16t^2 + 40t + 6. 
Will you be able to throw the ball over the wire?
:
Find the max height:
the axis of symmetry;
 t = {{{(-40)/(2*-16)}}}
 t = 1.25 secs
:
Find the max height
h = -16(1.25^2) + 40(1.25) + 6
h = -16(1.5625) + 50 + 6
h = -25 + 56
h = 31 ft, the answer is no