Question 286241
Q1) |2x-1|>5 for x. 
Solve 2x-1<-5 or 2x-1>5
2x < -4 or 2x > 6
x < -2 or x > 3
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Q2) Sketch the graph of the equation y= 2x^2 - 8x + 11 using the intercepts and vertex. 
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Vertex at x = -b/2a = 8/4 = 2
f(2) = 2(4)-8(2)+11 = 3
Vertex: (2,3)
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y-intercept when x = 0
(0,11)
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Sketch:
{{{graph(400,300,-10,10,-10,10,2x^2-8x+11)}}}
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Q3) tan(theta) = - square root of 3, find (theta) for 0 < (theta) < 2 pie
x = tan^-1(-sqrt(3)) = 300 degrees or 120 degrees
 
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Cheers,
Stan H.
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