Question 286260
(8x^2 - 10x - 3)/(8x^2 - 6x - 9) =

((4x+1)*(2x-3))/((4x+3)*(2x-3)) =

(4x+1)/(4x+3)   

*Note that (2x-3)/(2x-3) = 1 so those terms cancelled out.