Question 285880
Numerator is 6
Denominator is 2 times the radical expression square root of five plus 2. 
:
Assume the problem is:
{{{6/(2sqrt(5)+2)}}}
We have to multiply the expression by the conjugate of the denominator over itself
(same as multiplying by 1)
{{{6/(2sqrt(5)+2)}}} = {{{(2sqrt(5)-2)/(2sqrt(5)-2)}}}
FOIL the denominators, the middle term cancels, get rid of the radical
{{{(6(2sqrt(5)-2))/(4(5)-4)}}} = {{{(6(2sqrt(5)-2))/16}}}
You can factor out the 2 in the denominator and you have
{{{(12(sqrt(5)-1))/16}}}
reduce the fraction 12/16 to 3/4
{{{(3(sqrt(5)-1))/4}}}
Multiply inside the brackets, give the answer that you have
{{{(3sqrt(5)-3)/4}}}