Question 285775
Call the width of the photo {{{x}}} in, then
the length is {{{2x - 1}}} in.
the area of the photo is 
{{{x*(2x - 1) = 2x^2 - x}}}
The area of the photo plus border is
{{{(x + 6)*(2x - 1 + 6)}}}
{{{(x + 6)*(2x + 5)}}}
{{{2x^2 + 17x + 30}}}
The area of photo plus border is {{{130}}} in2
{{{2x^2 + 17x + 30 = 130}}}
{{{2x^2 + 17x - 100 = 0}}}
using quadratic equation:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{a = 2}}}
{{{b = 17}}}
{{{c = -100}}}
{{{x = (-17 +- sqrt( 17^2-4*2*(-100) ))/(2*2) }}} 
{{{x = (-17 +- sqrt( 289 + 800 ))/4 }}}
{{{x = (-17 +- 33)/4 }}}
{{{x = (-17 + 33)/4}}}
{{{x = 16/4}}}
{{{x = 4}}}
{{{2x - 1 = 2*4 - 1}}}
{{{2x - 1 = 7}}}
Area of photo = {{{4*7}}}
{{{4*7 = 28}}} in2
The answer is (B)