Question 285914

The first part of the problem says to substitute three + values , 3 - values, and 0 for x

y=2^-(x-2), x=2^-(y-2)
so plug in 3 + values such as 1 2 and 3
three negative values -1 -2 -3
and 0
do that much and we can proceed. 

for x=1
y=2^-(x-2)
x=1
y=2^-(1-2)
work it out
x=2^-(y-2)
1=2^-(y-2)
work it out