Question 285834
Breath in, breath out, we WILL get thru this! LOL

If I understand this correctly we have the cubed root of the entire quantity 729x^14/y^3, correct?
Look what we have, some perfect cubes!!!
let's pull the 9 out of the numerator and from underneath the radical, let's do the same for the y in the denominatorso we get 9/y TIMES cubed root of x^14. (YOU MUST KNOW THE LAWS OF EXPONENTS--GO BACK AND REVIEW!!!) x^14(1/3) is the same as cubed root of x^14. x^14/3 =x^4 with 2/3 left, soo
we also pull an x^4 out. NOW we have a 9x^4/yTIMES x^2/3=9x^4/y TIMES cubed root of x^2

9x^4/y TIMES cubed root of x^2, this is the answer! is this clear? let me hear from you Be sure to put 'cube problem' in your response.