Question 285746
ln (2x + 3) = 2
Your equation is in the form
log(expression) = other-expression
With an equation of this form, with the variable in the argument of a logarithm, you rewrite the equation in exponential form and solve that equation:
{{{2x+3 = e^2}}}
Now we solve for x:
{{{2x = e^2 - 3}}}
{{{x = (e^2 - 3)/2}}}
This is the exact solution. For a decimal approximation, use your calculator on the right side. (If you don't know how to get "e" on your calculator, then use 2.7182818284590451 for "e".)