Question 285563
The general rule is:
{{{log(a) - log(b) = log(a/b)}}}, so
{{{log(x-3) = log(x) - log(2)}}}
{{{log(x-3) = log(x/2)}}}
If the logs are equal, the quantities are equal
{{{x - 3 = x/2}}}
{{{2x - 6 = x}}}
{{{x = 6}}}
The answer is (C)