Question 285289
x/(x-2)=1/2-(x+2)/x



2x(x-2)[x/(x-2)]=2x(x-2)[1/2]-2x(x-2)[(x+2)/x]



2x^2=x(x-2)-2(x-2)(x+2)



2x^2=x^2-2x-2x^2+8


3x^2+2x-8=0


(x+2)(3x-4)=0


x=-2 or x=4/3 <--------------- Answers