Question 34437
OK, consider the equation {{{ y = mx + b }}}

You substitute the slope give in for m. and subsitute the y-intercept in for b.

However, I believe standard form is  {{{ Ax + By + C = 0 }}}.

Essentially in order to do this take it from the form of y=mx+b and multiply everything by the denominator of the slope, and finally get everything on one side of the equation setting it equal to zero.

For an example:
Let's say we have a slope of 3/2 and a y-intercept of 2, then we should end up with:
{{{ m = 3/2 }}}, and {{{ b = 2 }}}, therefore we end up with the slope-intercept equation of:

{{{ y = (3/2)x + 2 }}} to convert this to standard form, mulitply everything by 2 (because that is the denominator of 3/2 ).


So we get {{{ (2)*y = (2)*(3/2)x + (2)*2 }}}, resulting in 

{{{ 2y = 3x + 4 }}} ,but we still have to get everything on ONE side of the equal sign, BUT a special rule you must not... the coefficient A... MUST ALWAYS be positive, never negative so you have to make the appropriate adjustments.

So, my suggestion in this example is- since 3x is already positive (the 3 is positive) bring the 2y to the right side of the equation (leaving zero in its place).

{{{ 2y - (2y) = 3x - (2y) + 4 }}}, resulting in 
{{{ 0 = 3x - 2y + 4 }}}, but rearrange with zero on the right side!

{{{ 3x-2y+4 = 0 }}}