Question 285198
2x/(x+2)-2=(x-8)/(x-2)
2x-2x-4)/(x+2)=(x-8)/(x-2)
-4/(x+2)=(x-8)/(x-2)
-4(x-2)=(x-8)*(x+2)
-4x+8=x^2-16x+2x-16
0=x^2-8x+2x+4x-8-16
0=x^2-2x-24
*[invoke quadratic "x", 1, -2, -24 ]