Question 285010
Let one leg be x

the other leg = x-2

x^2 + (x-2)^2= 10^2

x^2+x^2-4x+4=100

2x^2-4x-96=0  divide equation by 2

x^2-2x-48=0

x^2-8x+6x-48=0

x(x-8)+6(x-8)=0

(x-8)(x+6)=0

x=8 0r -6

So x is 8 which is a positive value