Question 285057
If the measures of three angles in a triangle are (2x+1), (3x-23), and (3x+18).

The sum of all angles of a triangle = 180 deg.

(2x+1)+(3x-23),+ (3x+18)=180

8x-4=180

8x=184
x=184/8

x= 23

2x+1= 46+1= 47 deg

3x-23= 46 deg

3x+18= 87 deg