Question 284715
The first step in such a problem is to solve the given equation for y.
{{{x-2y=3}}} So subtract x from both sides.
{{{-2y=3-x}}} Now divdie everything by -2.
{{{y=-3/2 + (1/2)*x}}} The number attached to the x is the slope of this line, {{{1/2}}} To get a line that is perpendicular you need to take the negative reciprocal which would be {{{-2/1}}} or just -2.
We now do {{{y=mx+b}}} m stands for slope so we have.
{{{y=-2x+b}}} Now you plug in (4,-7), 4 for x and -7 for y to get the line that passes through that point and solve for b.
{{{-7=-2*4+b}}}
{{{-7=-8+b}}} add 8 to both sides.
{{{1=b}}}
Going back to {{{y=-2x+b}}} you will now put in the b you found.
And {{{y=-2x+1}}} is your final answer.