Question 284735
first equation is 3x + 6y = 48
second equation is -5x + 6y = 32


subtract second equation from first equation to get:


8x = 16


divide both sides of this equation by 8 to get:


x = 2


replace x with 2 in the first equation to get:


6 + 6y = 48


subtract 6 from both sides of this equation to get:


6y = 42


divide both sides of this equation by 6 to get:


y = 7


your answer should be x = 6 and y = 7.


substitute these values in both original equations to get:


first equation is 3x + 6y = 48
second equation is -5x + 6y = 32


3x + 6y becomes 3*2 + 6*7 = 6 + 42 = 48 confirming x and y are good in the first equation.


-5x + 6y = 32 becomes -5*2 + 6*7 becomes -10 + 42 = 32 confirming x and y are good in the second equation.


your answer is:


x = 2 and y = 7