Question 284341
The sum of two numbers is 56.
If the larger number is divided by the smaller number, the quotient is 1 with a remainder of 16. What are the two numbers? 
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Equations:
x + y = 56
x/y = 1 + 16/y
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Multiply thru the 2nd equation by "y":
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x + y = 56
x = y + 16
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Rearrange:
x + y = 56
x - y = 16
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Add and solve for "x":
2x = 72
x = 36
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Substitute for "x" and solve for "y":
36 + y = 56
y = 20
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Cheers,
Stan H.