Question 284319
You have randomly queried 400 local adults and determined that 150 of them watched the last episode of the show. 
>> create a 95% confidence interval for the proportion of folks in the population that viewed the show 
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Sample proportion = 150/400 = 15/40
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standard error = E = 1.96*sqrt[(15/40)(25/40)/400] = 1.96*0.0242 = 0.0474
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95% CI: (15/40)-0.0474 < p < (15/40)+0.0474
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95% CI: 0.3276 < p < 0.4224
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Cheers,
Stan H.