Question 283190
{{{ x(x + 2) = 3(2x + 2) - 1 }}}<br>
Expand:
{{{ x^2 + 2x = 6x + 6 - 1 }}}<br>
Subtract 6x + 5 from each side:
{{{ x^2 - 4x - 5 = 0 }}} <br>
Now that the equation is in the classic {{{ ax^2 + bx + c = 0 }}} form you can solve it like any other quadratic equation. 
Remember that this is solving for the <i>lower number</i>, so use it and the next consecutive higher integer and check them to make sure they fit the criteria in the question and bob's your uncle!