Question 284238
[m - 2 divided by 3m + 9] times [m^2 + 6m + 9 divided by 2m^2 - 8]
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[(m-2)/(3(m+3))] * [ (m+3)^2/(2(m-2)(m+2))]
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Cancel: (m+3), (m-2)
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[1/3]*[(m+3)/(2(m+2)]
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= (m+3)/(6(m+2))
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Cheers,
Stan H.