<PRE><B>Question 284055</B>
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No can do.  Nobody can.  You cannot write &lt;b&gt;&lt;i&gt;the&lt;/i&gt;&lt;/b&gt; equation of a line.  You can write &lt;b&gt;&lt;i&gt;an&lt;/i&gt;&lt;/b&gt; equation of  a line.


The slopes of parallel lines are identical, that is to say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \parallel\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ m_2]


So, put your equation into slope-intercept form by solving for *[tex \Large y].  Here all you have to do is add *[tex \Large 3x] to both sides.  Once the given equation is in slope-intercept form, that is: *[tex \Large y\ =\ mx\ +\ b], you can determine the slope just by examining the coefficient on *[tex \Large x].


Now that you know the slope of the given line, you also know the slope of the desired line.


Use the Point-Slope Form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


Where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the slope determined from the given equation.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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