Question 34339
{(3x+9)/(x^2-x-12)} * {(x^2+5x+6)/(24x+48)}
={3(X+3)/(X^2-4X+3X-12)}*{X^2+3X+2X+6)/24(X+2)}

={3(X+3)/(X(X-4)+3(X-4))}*{(X(X+3)+2(X+3))/24(X+2)}
={3(X+3)/(X+3)(X-4)}{(X+3)(X+2)/24(X+2)}
={3/(X-4)}{(X+3)/24}
=(X+3)/8(X-4)