Question 283763
In algebgra.com language, the answer is:


log(4,(64*256)) = log(4,64) + log(4,256)


After being put through the algebra.com formula generator, the answer looks like this:


{{{log(4,(64*256)) = log(4,64) + log(4,256)}}}


In english, the answer is:


log(64*256) to the base of 4 is equal to log(64) to the base of 4 plus log(256) to the base of 4.


In your language, the answer is:


log[4](64*256) = log[4](64) + log[4](256).


This is because, in general:


log(b,a*c) = log(b,a) + log(b,c)