Question 283802
let one integer be x

four times integer = 4x

4x-5 is the second number

x(4x-5)=21

4x^2-5x-21=0

4x^2-12x+7x-21=0

4x(x-3)+7(x-3)=0

(x-3)(4x+7)=0

SO x= 3 or -7/4

but the integer is positive so x=3 

the other number = 12