Question 283745
A group of 8 children is chosen from a class with 30 boys and 10 girls. what is the probability that the group contains at least one boy
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P(at least one boy) = 1 - P(no boy)
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P(at least one boy) = 1 - [10C8/30C8]
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P(at least one boy) = 1 - 45/5852925 = 0.000007688...
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Cheers,
Stan H.