Question 283728
3s+3h=2250
5s+2h=2400
so we have two equations with two unknowns.
we can solve by substitution or elimination(aka addition)
lets try elimination
multiply the first equation by -2 and the second by 3
-6s-6h=-4500
15s+6h=7200
add them
9s=2700
s=300
plug 300 for s in any equation and solve for h
3s+3h=2250
3*300+3h=2250
900+3h=2250
3h=1350
h=450
s=300