Question 34340
both fractions have the same denominator, so 


{{{ ((3x-1)/(x^2+5x-6)) - ((2x-7)/(x^2+5x-6)) }}} becomes
{{{ ((3x-1)-(2x-7))/(x^2+5x-6) }}}
{{{ (3x-1-2x+7)/(x^2+5x-6) }}}
{{{ (x+6)/(x^2+5x-6) }}}
{{{ (x+6)/((x+6)(x-1)) }}}
{{{ 1/(x-1) }}}


jon