Question 283698
SOLVE : 
4\X-3 + 2X\X-3 = 12\X^2-6X+9

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Multiply thru by x^2-6x+9 = (x-3)^2
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4(x-3) + 2x(x-3) = 12
4x-12 + 2x^2-6x = 12
2x^2 -2x -24 = 0
x^2 -x - 12 = 0
(x-4)(x+3) = 0
x = 4 or x = -3
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Cheers,
Stan H.