Question 283677
A population has a standard deviation of 50. 
A random sample of 100 items from this population is selected. 
The sample mean is determined to be 600. 
At 95% confidence, the margin of error is
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E = ts/sqrt(n)
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E = t(0.975, df= 99)*50/sqrt(100)
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= 1.9842*50/10 
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= 9.9211..
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Cheers,
Stan H.