Question 283683
{{{dk+3dm-2ek-6em}}} Start with the given expression.



{{{(dk+3dm)+(-2ek-6em)}}} Group the terms into two pairs of groups



{{{d(k+3m)+(-2ek-6em)}}} Factor out the GCF 'd' from the first group.



{{{d(k+3m)-2e(k+3m)}}} Factor out the GCF '-2e' from the second group.



{{{(d-2e)(k+3m)}}} Factor out the GCF {{{k+3m}}} from the entire expression.



So {{{dk+3dm-2ek-6em}}} factors to {{{(d-2e)(k+3m)}}}



In other words, {{{dk+3dm-2ek-6em=(d-2e)(k+3m)}}}