Question 283560
To solve this problem by substitution method:
2x - 3y = -25
3x + y = 1

If you notice in the second equation, there is a y by itself (no number attached):
{{{3x + y = 1}}}

First, subtract the 3x from the left to the right side of the equation:

{{{y = -3x + 1}}}

Now place the y equals into the first equation:

{{{2x - 3y = -25}}}
{{{2x - 3(-3x + 1) = -25}}}

Now follow order of operations:
Remember: Negative X Negative = Positive
{{{2x + 9x - 3 = -25}}}

Now add like terms, x's:

{{{11x - 3 = -25}}}

To get 11x by itself, add the 3 from the left to the right side of the equation:

{{{11x = -25 + 3}}}

{{{11x = -22}}}

{{{11x/11 = -22/11}}}
{{{x = -2}}}

Now you have the value of x, next place the x value into the first equation:

{{{2(-2) - 3y = -25}}}

{{{-4 - 3y = -25}}}

Next add the 4 from the left to the right side of the equation:

{{{-3y = -25 + 4}}}

{{{-3y = -21}}}

Divide by negative 3 to get y by itself, Negative/Negative = Positive:
{{{-3y/-3 = -21/-3}}}

{{{y = 7}}}

Check both your values, x = -2, y = 7

Place it into either equation I placed it into the first,
{{{2x - 3y = -25}}}
{{{2(-2) - 3(7)= -25}}}
{{{-4 - 21 = -25}}}
{{{-25 = -25}}}