Question 283356
Consider:
Odd numbers can be expressed as: 2k+1 (k a natural number)
Hence consecutive odds will be 2k+1 and 2k+3.

The sum of these two is 4k+4. Hence, the number must be even so case i is out.

4k+4=400 implies k=99.

So, 400 works. However, as per the tutor below there are additional cases to consider.


Now consider 3 odds.

2k+1,2k+3,2k+5. This gives 6k+9 as the sum. 6k+9=225 -> 6=16. So 225 fits the "or more" portion of the question. I hope this helps you see how to work the problem rather than just supplying the answer...