Question 283272
Your equation is:


h = 96t - 16t^2


You want to solve this equation for when h = 0.


Your equation becomes:


-16t^2 + 96t = 0


Divide both sides of this equation by 16 to get:


-t^2 + 6t = 0


Factor out the t to get:


-t * (t-6) = 0


This equation will be true if -t = 0 or (t-6) = 0 or both are 0.


Solve for t and you get:


t = 0 or t = 6.


Graph your original equation of -16t^2 + 96t = 0 as shown below:


{{{graph(300,300,-10,10,-150,150,-16x^2 + 96x)}}}


Note that in order to graph this equation, you needed to substitute x for t so your equation becomes y = -16x^2 + 96x.