Question 283300
let the number be x

the second number will be x+2

the product will be x(x+2)

 three times the sum less 1 = 3(x+x+2)-1

x(x+2)=3(2x+2)-1

x^2+2x=6x+6-1

x^2+2x-6x=+6-1

x^2-4x=+5

x^2-4x-5=0

x^2-5x+x-5=0

x(x-5)+1(x-5)=0

(x+1)(x-5)=0

x=-1 or 5  

So 5 & 7 are the numbers