<PRE><B>Question 283317</B>
What is the perimeter and area of the rectangle the top side is 3+6 times the square root of 2 yards and the right side is the square root of 8 yards.

length = 3+6sqrt2

width= sqrt8

perimeter = 2(3+6sqrt2) + 2 (sqrt8)

= 6+12sqrt2+2sqrt8

=6+12sqrt2+2*2 sqrt2-----------------  2sqrt8 = 2sqrt (2*4)=2sqrt2*sqrt4 =4sqrt2

=6+12sqrt2+4sqrt2

=6+16sqrt2  yards = perimeter

Area = L*W

= (3+6sqrt2)*2sqrt8
=(3+6sqrt2)*4sqrt2
=4sqrt2 +24sqrt2
=28sqrt2 square yards  is the area




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